Y=16t^2+40

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Solution for Y=16t^2+40 equation: 



=16Y^2+40

We move all terms to the left:

-(16Y^2+40)=0

We get rid of parentheses

-16Y^2-40=0

a = -16; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·(-16)·(-40)
Δ = -2560
Delta is less than zero, so there is no solution for the equation

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